n=2(-2)^2-5

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Solution for n=2(-2)^2-5 equation: 



n=2(-2)^2-5

We move all terms to the left:

n-(2(-2)^2-5)=0

We add all the numbers together, and all the variables

n-3=0

We move all terms containing n to the left, all other terms to the right

n=3

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